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STatiana [176]
3 years ago
12

Two six-sided dice are rolled. Find the probability that the sum of the two faces that turn up is between 1 and 14.

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

100%

Step-by-step explanation:

100 percent.

No matter what, the sum of the two faces that turn up will be between 1 and 14.

This means that it will occur, 100 percent of the time, or 10 out of 10 times.

Since each die is 1-6, the sum of the two faces will always be between 2 and 12.

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We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

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ANSWER


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EXPLANATION


The perimeter of triangle OQR is the sum of the distance around the triangle.



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