Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.
Let's see if there are anything we missed:
∞
Σ 2^n=1+2+4+8+16+...
n=0
We multiply (2-1) on both sides:
∞
(2-1) Σ 2^n=(2-1)1+2+4+8+16+...
n=0
And we expand;
∞
Σ 2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)
n=0
But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:
∞
Σ 2^n=-1+2(2^n)
n=0
If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.
Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.
Yep, this shows how weird the infinity sign is.
Answer:
x=-2
Step-by-step explanation:
-6/18=x/6
simplify the -6/18 into -1/3,
-1/3=x/6
cross product,
3*x=-1*6
3x=-6
x=-6/3
x=-2
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hope this helped
mark brainliest :)
Answer:
No solution
Step-by-step explanation:
There is one variable. so it can't be two solutions. To the rest, we need to solve the equation.
5-2x=3+x-4-3x
5=3-4
5=-1
Impossible!!!
so no solution.
Hope this helps plz mark brainliest :D
Answer:
186
Step-by-step explanation:
