A
41 is not divisible by any number other than 1 and itself so it is prime and not composite and obviously 41 is a whole number so BCD are eliminated
Answer: (b)
x g(x)
1 -16
2 -12
3 -8
If g(x) is 4*f(x), then we can find g(x) by multiplying 4 by x-5
g(x) = 4(x-5)
= 4x-20
Now we can plug in 1,2, and 3 for x to see which table makes sense.
g(1) = 4(1) - 20
= -16
g(2) = 4(2) - 20
= -12
g(3) = 4(3) - 20
= -8
hope this helps
Answer:
I think that the answer in NO
Step-by-step explanation:
Answer:16:18
Step-by-step explanation:
Answer:
Step-by-step explanation:x+y+z=100(let x ,y,z represent the first second and third numbers respectively)
Therefore,y=2z
z=x-8
y=2x-16
substituting the values of x,y and z into the question,we have
x+(2x-16)+(x-8)=100
Simplifying,we have
4x-24=100
adding 24 to both sides of the equation,
4x=100+24
4x=124
dividing both sides of the equation by the co-efficient of x,we have
4x/4=124/4
4.31=124
therefore,x=31.
