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laila [671]
3 years ago
11

6+ a/4= -5

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer # 1: 6+ a/4= -5 Answer # 2: n = 24

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The following section is a statement from the rental agreement Tim signed when he rented his car this past weekend. "Upon checko
AlexFokin [52]

Based on the fact that Tim forgot to refuel the vehicle and the amount per gallon at the rental place, Tim will have to pay an extra amount of d. <u>$57.88.</u>

<h3>How much will Tim pay?</h3>

According to the conditions, Tim will have to pay for the complete refueling of the car should he forget to refuel. He will also have to pay a $5.00 refueling fee.

The car is almost empty which means he will also pay for the entire capacity of the car.

The amount Tim will pay is:

= (Cost per gallon x Total fuel capacity) + Refueling fee

= (4.50 x 11.75) + 5

= $57.88

In conclusion, option D is correct.

Find out more on car rental repayments at brainly.com/question/6034138.

5 0
2 years ago
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
4 years ago
If m angle ABC=180. What is the degree measure of angle ADC
Damm [24]

Answer:

if ∠ABC = 180°,

then, 2x∠ADC = ∠ABC ( angles subtended by an arc at the center is double the angle subtended it at any point on the remaining part if the circle)

{ please read the theorem carefully as i know u wont be able to understand it at first try :) }

therefore ∠ADC = 90°

4 0
4 years ago
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Solid figure with a pentagon for a base and triangular faces
mafiozo [28]
It's a pentagonal pyramid. 
6 0
4 years ago
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6x6=? 00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
Kamila [148]

THE AnSwEr is ttttttttttttttttthhhhhhhhhhhhhhhiiiiiiiiiiiiiirrrrrrrrrrrttttttttttttyyyyyyyyyyyy ssssssssssssssssssiiiiiiiiiiiiiiiiiiiiiixxxxxxxxxxxxxxxx

33333333333333333333333333336666666666666666666666666666666666

5 0
3 years ago
Read 2 more answers
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