If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
Answer: 16
Step-by-step explanation:
9,10,12,x ,20, 25 so we know the median is 14 which is the middle number.
Since the numbers are 6 it means there will be 2 middle numbers and if you divide them it will be 14.
we know one of the middle numbers is 12 and we trying to find x .
So we could use the equation x + 12 = 2(14)
x + 12 = 28
-12 -12
x= 16 so X is 16. check: 16+12=28/2 is 14.
Answer:
1/2
Step-by-step explanation:
First create like dominators
2/3 -1/6 = 4/6 - 1/6
simplify using subtraction
4/6 - 1/6 = 3/6
Simplify the answer
3/6 = 1/2
Answer:
28 minutes
3.5 x 8 = 28
Step-by-step explanation:
Feeding the whole school (8/8) would take 8 times as long as feeding 1/8 of the school.
3 1/2 can become 3.5 if that's easier for you to work with.
Feeding 1/8 of the school is 3.5 x 1 = 3.5
Feeding 2/8 of the school is 3.5 x 2 = 7
Feeding 8/8 of the school is 3.5 x 8 = 28
It takes 28 minutes to feed the whole school (8/8)
The highest common factor is 45
