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Aleonysh [2.5K]
3 years ago
5

How do you get 25 though plz urgent answer

Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

what do you mean by 25 though

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Evaluate. 7 x (-7 + 15)
tia_tia [17]

Answer:

56

Step-by-step explanation

3 0
3 years ago
Under her cell phone plan, Rajani pays a flat cost of $65 per month and $5
riadik2000 [5.3K]
If she wants to only use 85 a month then doing the math it would be 85-65=20 divided by 5 equals 4 so she would get 4 gigabytes while staying within her budget :)

Brainiest please
3 0
3 years ago
Graph f(x) = 5x - 45
kakasveta [241]
Y= 5x-45

On your graph go by 5's
On the y go down 9 which going by 5 makes it -45
Then go up 5 and one to the right and plot points keep going. 25/5=5
8 0
3 years ago
Read 2 more answers
State the number of real zeros and what they are for "3x^2+5x-2" pleas help me:'(
Lady bird [3.3K]
This can be solved by factoring.

First, set the expression equal to zero.

3x^2+5x-2=0

Then, find two the factors of  ac whose sum is b.

6, -1

Split b into these two factors.

3x^2+6x-x-2=0

Next, factor by grouping.

3x(x+2)-1(x+2) = (3x-1)(x+2) = 0

By the Zero Product Property, set each factor equal to zero.

3x-1 = 0 \\ x = 1/3

x+2=0 \\ x = -2

These are the solutions. The Complex Conjugate Root Theorem and the Fundamental Theorem of Algebra both state that, in essence, real and imaginary solutions come in pairs of two and every polynomial of degree n has exactly n complex roots, but real roots are also complex roots. That sounds confusing, but this just means that you're done. Your answers are -2 and 1/3. There are two real roots.
3 0
3 years ago
Find the least common multiple of 10x4 and 6w3 .
jarptica [38.1K]
10x⁴ and 6w³

1) We see no the same letters in both expressions, so we will need to include all letters in the final answer. x⁴w³

2) number part
10 = 2*5
6=3*2
We need 2*3*5=30  (we need 2 only one times, because we have 2 only one time in each of the numbers).
3)The least common multiple
2*3*5x⁴w³ = 30x⁴w³
Answer is  30x⁴w³.

8 0
3 years ago
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