All categories

3 years ago

What is the angle of rotation for the following figure? // pls answer .

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:I THINK 180

Step-by-step explanation: HOPE THIS HELPS

You might be interested in

Plz help me i need help before 1/28/22

garik1379 [7]

Answer:

3/4

Step-by-step explanation:

three-fourths also means 3 out of 4. This can be shown as a fraction as 3/4

5 0

2 years ago

Read 2 more answers

A single gram of a certain metallic substance has 0.52 g of copper and 0.25 g of zinc the remaining portion of the substance is

andrezito [222]

Ben's estimate gives 7 g of nickel; the actual amount is 8.03 g.

In 1 g of the substance, there is 0.52 g of copper and 0.25 g of zinc; this gives
0.52+0.25 = 0.77 g of the substance.

The remaining part of the substance is nickel:
1-0.77 = 0.23 g of nickel.

Using Ben's estimate, 0.2 g of nickel per gram of substance, we have
0.2(35) = 7 g of nickel in 35 g of the substance.

The actual amount is 0.23(35) = 8.03 g of nickel in 35 g of the substance.

6 0

3 years ago

Help help help help help help

Furkat [3]

$\huge\bold{\purple{\bold{⚡133°⚡}}}$

Step-by-step explanation:

Co interior angles' sum is 180°

So, 180-67=133
133°

5 0

2 years ago

Need help with this confusing

Dahasolnce [82]

Answer:

The blanks are 18 and 20

equivalent ratios

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Suppose that contamination particle size (in micrometers) canbe modeled as

asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

$f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1$

a) probability density function.

$\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1$

Thus, it is a probability density function.

b) cumulative distribution function.

$P(X$

c) mean of the distribution

$\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2$

d) probability that the size of random particle will be less than 5 micrometers

$P(X$

4 0

3 years ago