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Damm [24]
3 years ago
10

Mia invests $5,000 in an index fund. After 1 year, the fund's share price has increased by 8%. How much did Mia gain?

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer: In the end, she has $5400 in total, so she must gain $400 on her investment.

Step-by-step explanation:

8% is 0.08 >>> add 1 to it = 1.08

5000*1.08 = 5400

or the other way to do this is 5000*0.08 = 400 and then 5000+400=5400

Hope this helps!

You might be interested in
Find the first 4 terms in each sequence​
koban [17]

Answer:

a₁ = -21  (Given)

a₂ = -28

a₃ = -35

a₄ = -42

Step-by-step explanation:

First term a₁ = -21  (Given)

…………………………………

Second term a₂ :

a₂ = a_{2-1} - 7\\a_{1} - 7\\a_{1} = -21\\-21 - 7 = -28

…………………………………

Third term a₃ :

a₃ = a_{3-1} - 7\\a_{2} - 7\\a_{2} = -28\\-28 - 7 = -35

…………………………………

Fourth term a₄ :

a₄ = a_{4-1} - 7\\a_{3} - 7\\a_{3} = -35\\-35 - 7 = -42

5 0
2 years ago
4. Divide, using synthetic division: 16x^3 +80x^2+x+5/x+5
fgiga [73]

Answer:

Step-by-step explanation:

x+5=0

x=-5

-5) 16   80   1    5

  |       -80   0  -5

 ____________

  | 16    0    1  | 0

quotient=16x²+1

Remainder=0

8 0
3 years ago
First try was incorrect
Veronika [31]

Answer:

Circumference = 2(pi)r

C = 2*3.14*4.0= 25.12 round 25.10 m

Step-by-step explanation:

7 0
3 years ago
Compare 5/12 and 7/12 by comparing them to a benchmark fraction on the number line
aivan3 [116]
Compare it to 1/2 (which is the same as 6/12)
6 0
3 years ago
Suppose in the population, the Anger-Out score for men is two points higher than it is for women. The population variances for m
tatuchka [14]

Answer:

a)= 2

b) 6.324

c) P= 0.1217

Step-by-step explanation:

a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)

b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by

σ_X`1- X`2 = √σ²/n1 +σ²/n2

Var ( X`1- X`2) = Var X`1 + Var X`2 =  σ²/n1 +σ²/n2

so

σ_X`1- X`2 =√20 +20 = 6.324

if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.

Where as Z is normally distributed with mean zero and unit variance.

If we take X`1- X`2= 0 and u1-u2= 2  and standard deviation of the sampling distribution = 6.324 then

Z= 0-2/ 6.342= -0.31625

P(-0.31625<z<0)= 0.1217

The probability would be 0.1217

8 0
2 years ago
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