The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer: x*3 -6=12
Explanation: I assume you wanted that put into an equation
A direct variation equation is in the form y = kx. So if you solve this equation will you get it in that form? No you will get y = 16/x. This is an inverse variation.
20 divided by 10 is 2
10 divided by 2 is 5 so it's 2/5
