The number of buckets is directly proportional to the area and the thickness of the wall and inversely proportional to the amount of paint. Mathematically, we can write:
n = k · (a · t) / p
where k is the proportionality constant which we do not know.
We can calculate k with the given data: 5 2-gallon buckets, area of 100 square feet and thickness 3 inches:
k = (n · p) / (<span>a · t)
= (5 </span>· 2) / (100 · 3) = 0.0333
Now that we know the constant, we can calculate the area that can be painted with 8 2-gallon buckets if the thickness is 6 inches:
a = (n · p) / (k<span> · t)
= (8 </span>· 2) / (0.0333 · 6)
= 80 ft²
Please, note that we made sure to have the exact same units of measurements than the previous case.
Therefore, the correct answer is an area of 80 ft².
Answer: option d. C (0,3), D (0,5).
Justification:
1) The x - coordinates of the vertices A and B are shown in the diagrama, They are both - 4, so the new vertices C and D must be in a line parallel to y = - 4.
2) The y-coordinates of the vertices A and B are also shown in the diagrama. They are equal to 3 and 5 respectively.
3) We can see that the new points C and D must be over a parallel line to y = - 4 and that their distance to the points A and B has to be the same distance of the point R and S to U and T.
That distance is 4, so the line may be y = - 7 or y = 0.
4) If the line is y = 7 the points C and D would have coordinates (-7,3) and (-7,5), but this points are not among the options.
5) If the line is y = 0 the points C and D would have coordinates (0, 3) and (0,5), which is precisely the points of the option d. That is the answer.
Hello.
We have:
- A point that the line passes through
- The slope of the line
Plug the values into the Point-Slope Formula:





I hope it helps.
Have a nice day.

Answer:
24th day will be the first day on which Tyler will wear his jackets and scarf to school
Step-by-step explanation:
We can find the first day on which the Tyler will wear his jackets and scarf to school by taking the LCM of(3,8)
<u>Finding the LCM of(3,8)</u>
List all prime factors for each number.
Prime Factorisation of 3 shows:
3 is prime => 
Prime Factorisation of 8 is:
2 x 2 x 2 => 
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new super-set list is
2, 2, 2, 3
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 3 = 24