Answer:
penetrating electromagnetic radiation of a kind arising from the radioactive decay of atomic nuclei.
Explanation:
SO A: ELECTROMAGNETIC RADIATION
(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.
(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.
<h3>Electric field at a point on the Gaussian surface</h3>
The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;
E = λ/2πε₀r
where;
- λ is linear charge density
- ε₀ is permitivity of free space
- r is the position of the charge
<h3>At a distance of 5.5 m</h3>

<h3>At a distance of 2.5 m</h3>

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.
Learn more about electric field here: brainly.com/question/14372859
It'll have a higher frequency.
The product of (wavelength) times (frequency) for a wave
is always the same number ... it's the wave speed.
So if one of them is small, the other one has to be big.
Answer:
length f′0 when the eye is presbyopic and by a screen (the retina) at the distance d from the
Explanation: