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AVprozaik [17]
3 years ago
15

The sun is 60° above the horizon. Rays from the sun strike the still surface of a pond and cast a shadow of a stick that is stuc

k in the sandy bottom of the pond. If the stick is 19 cm tall, how long is the shadow?

Physics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

shadow length 7.67 cm

Explanation:

given data:

refractive index of water is 1.33

by snell's law we have

n_{air} sin30 =n_{water} sin\theta

1*0.5 = 1.33*sin\theta

solving for\theta

sin\theta = \frac{3}{8}

\theta = sin^{-1}\frac{3}{8}

\theta =  22 degree

from shadow- stick traingle

tan(90-\theta) = cot\theta = \frac{h}{s}

s = \frac{h}{cot\theta} = h tan\theta

s = 19tan22 = 7.67 cm

s = shadow length

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Since f_k=\mu_k N and N=mg, we can rewrite the first equation as:

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