Ask question

Ask question

All categories

3 years ago

7

Sound is heard louder in newly furnished room ,why?

2 answers:

garik1379 [7]3 years ago

6 0

A newly furnished room is likely to be more sparsely furnished, as clutter has yet to be introduced to the space. This means there will be more hard surfaces from which sound can bounce. This creates a noisier environment. The addition of throws, drapes, cushions, even tapestries will reduce reverberation.

REY [17]3 years ago

3 0

Answer: a newly furnished room causes sounds to be louder because the sound can bounce off of an object in the room. an empty room would have less noise because there are no objects to bounce off.

You might be interested in

What happens when an ionic compound is melted?

Dahasolnce [82]

It conducts electricity. This is because the electrons are able to move around more for it has gained energy, after being heated.

7 0

3 years ago

Please<br>help<br>me<br>with this problem

uranmaximum [27]

Answer:

speeding up

Explanation:

because its speeding up, theres going to be more newtons in the back

i really hope this is right, tell me if so

3 0

2 years ago

Given the wave function: Y(x,t) = 5sin27(0.2x - 3t); (x = meters, t = sec.): What are the amplitude, frequency, wavelength, angu

MariettaO [177]

Answer:

Explanation:

Y = 5 Sin27( .2x-3t)

= 5 Sin(5.4x - 81 t )

Amplitude = 5 m

Angular frequency ω = 81

frequency = ω / 2π

= 81 / (2 x 3.14 )

=12.89

Wave length λ = 2π / k ,

k = 5.4

λ = 2π / 5.4

= 1.163 m

Phase velocity =ω / k

= 81 / 5.4

15 m / s.

The wave is travelling in + ve x - direction.

3 0

3 years ago

Show how the alternative definition of power, found in your book, can be derived by substituting the definitions of work and spe

Harman [31]

Let us consider body moves a distance S due to the force F.

Hence the work by the body W = FS

If the force is not along the direction of displacement,then the work by a body for travelling a distance S will be -

$W=[ Fcos\theta]*S$ where $Fcos\theta$ is the component of the force along the direction of displacement.

$Hence\ W= FScos\theta$

$= F.S$

As per the question the power P is given as -

$P=\frac{W}{\delta t}$

$=\frac{F.S}{\delta t}$

$= F.\frac{S}{\delta t}$

$= \ F.V$

Hence alternative definition of power P = F.V

8 0

3 years ago

Read 2 more answers

PLS HELP, I AM WILLING TO MARK BRAINLIEST TO FIRST ANSWER AND HAS TOO BE RIGHT

Ann [662]

Weak winds that blow for short periods of time with a short fetch.

6 0

3 years ago

Read 2 more answers