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3 years ago

Father to his first biological son true or false?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

Answer:

True

Step-by-step explanation:

have a great day!

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What is the percent of increase from 40.2 to 98.9?

alekssr [168]

Answer:

146%

Step-by-step explanation:

To find the percent increase/decrease:

1. Subtract the original value from the new value.

2. Divide by the original value.

3. Multiply the decimal by 100 to convert to a percent.

98.9 - 40.2 = 58.7

58.7/40.2 = 1.46

1.46*100 = 146%

8 0

3 years ago

The freshman class will be selling carnations as a class project. What is the class's income after it pays the florist a flat fe

mr Goodwill [35]

INCOME FUNCTION F(c) = 2c - 200

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B%20%5Csqrt%5B40404504x%20%5Cfrac%7Bx05121y%20%5Csqrt%5By%20%7C4%7C%20%5D%7B%3F%7D

atroni [7]

Answer:

The answer is 12 |17|7|5

what is the question?

Step-by-step explanation:

stan bts

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2 years ago

What radical expression is not simplified?

rodikova [14]

B 2/10 is not simplified because you can divide each number by 2 reducing it to 1/5.

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

5 0

2 years ago

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