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2 years ago

Will mark brainlist plz anwser

Mathematics

2 answers:

den301095 [7]2 years ago

8 0

Answer:

1,740 is the width.

never [62]2 years ago

5 0

The width of the court is 30 feet!

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Write the equation in slope-intercept form. 4x+3y=18

Helen [10]

Answer:

y = -4/3x + 6

Step-by-step explanation:

1. 3y - 4x + 3y = 18 - 3y

2. 4x = -3y + 18

3. 18 - 4x = -3y + 18 - 18

4. -3/ -3y = 4x - 18 /3

5. y = -4/3x + 6

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2

PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given Trigonometric expression is

$\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }$

So, on rationalizing the denominator, we get

$\rm \: = \: \dfrac{sin\theta }{1 + cos\theta } \times \dfrac{1 - cos\theta }{1 - cos\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}}$

So, using this, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{1 - {cos}^{2}\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {sin}^{2}x + {cos}^{2}x = 1}}}$

So, using this identity, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{{sin}^{2}\theta }$

$\rm \: = \: \dfrac{1 - cos\theta }{sin\theta }$

Hence, 

$\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta } = \: \dfrac{1 - cos\theta }{sin\theta } }}} \\$

3 0

2 years ago

Read 2 more answers

How to solve -40=30m-16?

Gennadij [26K]

What I would do for this problem, is move all the terms that don't contain m to the right side, and then solve.
m = 4/5.

7 0

3 years ago

Read 2 more answers

Which shows a way to take apart 4?

zheka24 [161]

A half of 4 is 2 because 2+2=4

3 0

2 years ago

Read 2 more answers

Can someone please help with NUMBER 7?!! It’s my last one I will mark brainliest to the best answer

Nikolay [14]

Answer:

1, 3, 9, 27

Step-by-step explanation:

$a_n = 3^{n - 1}$

You need the first 4 terms, so let n = 1, and evaluate the expression. Then do the same for n = 2, n = 3, and finally n = 4.

n = 1

$a_1 = 3^{1 - 1} = 3^0 = 1$

n = 2

$a_2 = 3^{2 - 1} = 3^1 = 3$

n = 3

$a_3 = 3^{3 - 1} = 3^2 = 9$

n = 4

$a_4 = 3^{4 - 1} = 3^3 = 27$

7 0

3 years ago