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USPshnik [31]
3 years ago
11

However, since we have 3 sets of 4, what can we do with the two exponents to avoid expansion?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

To avoid expansion, you can just use the power of a power rule and multiply the two exponents from the start.

Step-by-step explanation:

(<em>x</em>^4)^3

= <em>x</em>^4×3

= <em>x</em>^12

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Point W has coordinates (4, -7). If it is reflected over the y -axis, what are the coordinates of its image?
Korolek [52]

Answer:

I thank it is D

Step-by-step explanation:

4 0
2 years ago
Inequality / Linear Systems Help - 30 points!
Sholpan [36]

They did not include the constraint for y ≤x+3 on the graph.

See attached picture with added constraint.

Using the 4 points that are given as the solution on the graph, replace t he x and Y in the original equation to solve and see which is the greater value.

Point (0,3) P = -0 +3(3) = 0+9 = 9

Point (1,4) P = -1 + 3(4) = -1 +12 = 11

Point (0,0) P = -0 + 3(0) = 0 + 0 = 0

Point (3,0) P = -3 + 3(0) = -3 + 0 = -3

The correct solution to maximize P is (1,4)

5 0
3 years ago
An electronics company produces​ transistors, resistors, and computer chips. Each transistor requires 3 units of​ copper, 1 unit
padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.

3. We write the matrix form as Ax=d

A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)

x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)

A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

With this formula the solution of x is x=\frac{d}{A} or x=A^{-1}d

4. We will find the inverse matrix A^{-1} using the formula:

A^{-1} = \frac{1}{detA} (C_{A})^{T}

a. det A

det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3

b. (C_{A})^{T}

C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)

C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)

(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T

(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

c.A^{-1}

A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)

5. As x=\frac{d}{A} or x=A^{-1}d, the solution of x is:

x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)

x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)

X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]

<u><em>Therefore:</em></u>

<u><em>a= 350 Transistors</em></u>

<u><em>b=0 Resistors</em></u>

<u><em>c=340 Computer chips</em></u>

4 0
3 years ago
What is the word form for 2.35?
Afina-wow [57]
The word form for 2.35 is
"two point three five".
8 0
3 years ago
3x+7=25 can some one help me with this problem it will be great
siniylev [52]

Answer =6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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