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USPshnik [31]
3 years ago
11

However, since we have 3 sets of 4, what can we do with the two exponents to avoid expansion?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

To avoid expansion, you can just use the power of a power rule and multiply the two exponents from the start.

Step-by-step explanation:

(<em>x</em>^4)^3

= <em>x</em>^4×3

= <em>x</em>^12

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Explain why the graph of the equation g(x) = -(x + 1 ) - 3 would be a parabola opening downward.
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Answer: Because the a-value is negative.

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k    where

  • "a" is the vertical stretch
  • -a is a reflection over the x-axis
  • h is the horizontal shift (positive = right, negative = left)
  • k is the vertical shift (positive = up, negative = down)

Given: g(x) = - (x + 1)² - 3

                    ↓

                 a= -1

Since the a-value is negative, the parabola will be reflected over the x-axis which will change the curve from (U-shaped) to (∩-shaped).

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4 years ago
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What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

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On a math test, Jessica answered 20% questions incorrectly. She answered 16 questions correctly. How many total questions did sh
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