Answer:
Option C.
Step-by-step explanation:
Given information:
Male-Full stop = 6, Male-Rolling stop = 16, Male-No stop = 4
Female-Full stop = 6, Female-Rolling stop = 15, Female-No stop = 3
Using the given information we get
Total number of males = 6 + 16 + 4 = 26
Total number of males = 6 + 15 + 3 = 24
Probability of No stop is
We need to find the number of males that would we expect to not stop at all.
Expected number of males = Number of males × Probability
Expected number of males = 
Expected number of males = 
Therefore, the correct option is C.
Limiting the number of digits right of the decimal point
In most cases, if the interest rate increases, the payment will also go up or increase.
<h3>What is the interest rate?</h3>
When you have a loan or debt, the interest rate refers to the amount of money per month, year, etc. that you paid for the benefit of having borrowed the money.
- This is usually a small percentage of the total debt.
<h3>What happens if the interest rate increases?</h3>
This increases your total debt, and therefore, you will need to pay more money every month or year.
Learn more about percentage in: brainly.com/question/8011401
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Answer:
B
Step-by-step explanation:
y is first so, 8,1 6,2 4,3 2,4 0,5
Answer:
<em>The rebate should be $220</em>
Step-by-step explanation:
<u>Demand Curve</u>
It's the relationship between price (P) and quantity (Q) demanded a certain product or service.
(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:
Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).
The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)
We set up the equation of the demand
Rearranging
Or
Simplifying
(b) The revenue function is Q times the price
Solving the equation of the demand for P
Thus, the revenue is
(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0
Solving
Q=560 units a week
For which the revenue is
And the price is
The rebate should be $600-$280=$220
