Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
Gradient is = 0.375
Step-by-step explanation:
Rise = 3
Run = 8
The unknown is the distance in kilometres
The given is the distance in miles=140 miles
1 mile=1.6093km
140 miles=?
140/1*1.6093km=225.302km
Therefore the 140 miles in km is 225.302km
Answer:
2 1/5
Step-by-step explanation:
2 3/4 divided by 1 2/4=2 1/5
7x-(x-y) = 7x - x + y = 6x + y
9a-(2b-a) = 9a+a-2b = 10a-2b
hope it helped
