Select all tables that could represent a function.<br> A. B. OR C.

A circle is centered at the point (-7, -1) and passes through the point (8, 7). The radius of the circle is 13 units. The point

baherus [9]

The standard form of the equation of circle is:

(x – h)^2 + (y – k) ^2 = r^2

Where the center being at the point (h, k) and the radius being r

Substituting the values to the equation:

64 + (y +1) ^2 = 169

(y +1) ^2 = 105

y + 1 = 10.247

3 0

3 years ago

Write the first trigonometric function in terms of the second for θ in the given quadrant.. sec θ, sin θ; θ in quadrant I

Grace [21]

We have sec = 1/cos

Then we also have cos^2 = 1 – sin^2

Also we have cos = sqrt (1 – sin^2)

Substitute the derived cosine function to sec then we have

Sec = 1/(sqrt(1-sin^2)

3 0

4 years ago

Two terms in a geometric sequence are a3=729 and a4=243.

lesantik [10]

<h2>The first term of the given sequence (a) = 6561</h2>

Step-by-step explanation:

Let the first term = a and common difference = d

Given,

$a_{3}$ = 729 and $a_{4}$ = 243

To find, the first term of the given sequence (a) = ?

We know that,

The nth term of a G.P.

$a_{n} =ar^{n-1}$

The 3rd term of a G.P.

$a_{3} =ar^{3-1}$

⇒ $ar^{2}$ = 729 ..............(1)

The 4th term of a G.P.

$a_{4} =ar^{4-1}$

⇒ $ar^{3}$ = 243 ..............(2)

Dividing equation (2) by (1), we get

$\dfrac{ar^{3}}{ar^{2}}$ = $\dfrac{243}{729}$

⇒ $r=\dfrac{1}{3}$

Put $r=\dfrac{1}{3}$ in equation (1), we get

$a(\dfrac{1}{3})^{2}$ = 729

⇒ $a(\dfrac{1}{9})$ = 729

⇒ a = 9 × 729 = 6561

∴ The first term of the given sequence (a) = 6561

8 0

3 years ago

Suppose Maria places $5500 in an account that pays 2% interest compound each year. Assume that no withdrawals are made from the

kykrilka [37]

Answer:

After 1 year: $5,610

After 2 years: $5,722.20

Step-by-step explanation:

Use the formula for periodic compounding interest, which is

A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.

Here, P = 5,500, r = 0.02 (that's 2% as a decimal), n = 1,

t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)

Plug the known values in to solve...

For 1 year...

A = 5,500(1 + 0.02/1)^(1*1)

A = 5,500(1.02)^1

A = 5,610

For 2 years...

A = 5,500(1 + 0.02/1)^(1*2)

A = 5,500(1.02)²

A = 5,722.20

5 0

4 years ago

The graph shows the function f(x). What is the function's average rate of change from x = 0 to x = 2? Enter your answer, as a si

Shkiper50 [21]

Answer:

It's been awhile since I've done this but wouldn't it be -2x

Step-by-step explanation:

6 0

3 years ago

Select all tables that could represent a function. A. B. OR C.