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worty [1.4K]
3 years ago
5

Find the total area of the kitchen floor that is to be tiled as shown below.

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

58

Step-by-step explanation:

There is two rectangles in this problem.

For the first one 5×10=50

And the second one is 2×4=8

So the final answer will be 58

Hope this helpedn

dybincka [34]3 years ago
3 0
The answer is 58m^2

split the figure into two rectangles and find the area of each
add the two areas

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For which equation is y = 7 a solution?
Natasha2012 [34]

Answer:B

Step-by-step explanation:

y - 26 = -19

y + 26 - 26 = -19 + 26

y=7

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3 years ago
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find the value of c that makes each trinomial a perfect square. then write the trinomial as a perfect square. the equation , x^2
mr Goodwill [35]
Therefore, the value of C should be (11/2)^2

<span>To square a fraction, take the square of the numerator and put it over the square of the denominator. So since 11^2=121 and 2^2=4, (11/2)^2
(11)^2/(2)^2=121/4
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
What is the inverse of the function f(x) = -6x - 7​
andreyandreev [35.5K]

Answer:

f - 1 (x)  = - x6 - 76

Step-by-step explanation:

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=−x6−76 f - 1 ( x ) = - x 6 - 7 6 is the inverse of f(x)=−6x−7 f ( x ) = - 6 x - 7 .

7 0
2 years ago
Tammy bought 20 pounds of flour for $11.<br> How many pounds of flour did she get per dollar?
frozen [14]

Answer:

1.82 pounds per dollar

Step-by-step explanation:

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6 0
2 years ago
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Find the exact value of cos theta​, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.
vova2212 [387]

Answer:

cos \theta = -\frac{8}{17}

Step-by-step explanation:

For this case we know that:

sin \theta = \frac{15}{17}

And we want to find the value for cos \theta, so then we can use the following basic identity:

cos^2 \theta + sin^2 \theta =1

And if we solve for cos \theta we got:

cos^2 \theta = 1- sin^2 \theta

cos \theta =\pm \sqrt{1-sin^2 \theta}

And if we replace the value given we got:

cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

cos \theta = -\frac{8}{17}

5 0
2 years ago
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