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Answer:
The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
90% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
It would help if we represent the information in form of two-ways table as shown below
The number of students who are not on probation is 104 students
There are 23 students who are not on probation and is satisfied is 81 students
The probability of students not on probation and is satisfied is 81/104
The number of students who are not on probation is 104 students
There are 23 students who are not on probation and is satisfied is 81 students
The probability of students not on probation and is satisfied is 81/104