Answer:
Two consecutive numbers whose squares differ by 33 are 16 and 17
Step-by-step explanation:
lets assume first number be x
since numbers are consecutive , so other number will be x + 1
From given information in question
(x + 1)² - x² = 33
⇒ (x² + 1² + 2x) - x² = 33 [ since (a+b)² = a² + b² + 2ab ]
⇒ x² + 1² + 2x - x² = 33
⇒ 2x + 1 = 33
⇒ 2x = 33 - 1
⇒ x = 32/2 = 16
so one number is x = 16 and other number is x + 1 = 16 + 1 = 17
lets recheck our solution
17² - 16² = 289 - 256 = 33 , And since difference is 33 , two required consecutive numbers are 16 and 17.
Answer:
(x-2)(x+1)
Step-by-step explanation:
Factor!
The area is the product of length and width, which is to say that the length and width are factors of the area.
Assuming the dimensions are integers, you want factors of 84 that differ by 5.
... 84 = 1×84 = 2×42 = 3×28 = 4×21 = 6×14 = 7×12
The last of these pairs differ by 5, so ...
- the length is 12 inches
- the width is 7 inches.
Answer:
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