<span>
3√(32x^8y^10)
= </span><span>3√(16*2 x^8y^10)
= 12x^4y^5 </span>√2
Hope it helps
The domain of a relation is all the x - values the relation can take, so:
domain = {-8, -6, 5}
The range, in addition, is all the y - values the relation can take, so:
range = {-3, -1, 0, 5}
Answer:
, or 



<em>Hope this helps and have a great day!!!</em>