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Korvikt [17]
3 years ago
11

Consider the salt shaker shown

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0
Hi can you post a pic of the question thanks
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At a pizza resturant they have a choice of 20 toppings. If a customer choosea two topping pizza find the probability that they o
Naddika [18.5K]

Answer: The probability is 1/190 = 0.005

Step-by-step explanation:

The probability of ordering two specific toppings out of 20 is:

For the first selection he can order 2 of them, peperoni or sausage, so the probability for the first selection is 2/20 = 1/10 (the number of correct options divided by the total number of options)

For the second selection we have only one option, because we assume that the other one was selected previously, here we also had a total of 19 toppings because one already was selected, the probability in this selection is 1/19.

The joint probability is equal to the product of those two probabilities:

P = (1/19)*(1/10) = 1/190 = 0.005

3 0
3 years ago
Please helpp<br> . What is the area of the blue figure? *
antiseptic1488 [7]

Answer:

465.5

Step-by-step explanation:

If you plug in the numbers into the formula.

base 1= 15

base 2= 34

height= 19

3 0
3 years ago
Read 2 more answers
Are the graphs of the lines in the pair parallel? Explain.<br><br> y = 3/7x + 11<br> –3x + 7y = 13
Kobotan [32]
Yes they will be parallel. Now you try to solve it.
5 0
3 years ago
Read 2 more answers
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
4 years ago
Form the intersection for the following sets.
a_sh-v [17]
The intersection is where the sets overlap. picture a Venn diagram (two overlapping circles). The intersection is only the overlap part. So for this problem that would be C. {20}
5 0
4 years ago
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