It is defined as a function that is sinusoidal in nature, and it has a domain of all real numbers and lies between the [a, a]where is the amplitude of the function.

As we know the sin function is represented by:

y = Asin(Bx) + C

Here,

A = The amplitude = 3

C = The vertical shift = 1

B - The period in terms of π

B = 2π/amplitude

B = 2π/4

B = π/2

The becomes:

$\rm y = 3sin(\dfrac{\pi }{2}x)+1$

Thus, the equation of the sin function is y = 3sin(πx/2) + 1, and the graph of the function is shown in the picture.

Learn more about the sin function here:

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3 0

1 year ago

Describe and correct the error in finding the difference of the polynomials

levacccp [35]

Answer:

4x+11 is the answer.

Step-by-step explanation:

( 4*2-x+3)-(3*2-5x-6)

=(8-x+3)-(6-5x-6)

=(11-x)-(0-5x)

=(11-x)-(-5x)

=11-x+5x

=11+4x

= 4x+11

6 0

3 years ago

An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can

serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0 ......[1]

the solution for the equation is given by:

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

On comparing the given equation with [1] we have;

a = -16 ,b = 80 and c = 300

then;

$t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}$

$t= \frac{-80\pm \sqrt{6400+19200}}{-32}$

$t= \frac{-80\pm \sqrt{25600}}{-32}$

Simplify:

$t = -\frac{5}{2}$ = -2.5 sec and $t = \frac{15}{2}$ = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0

3 years ago