Answer:none of these
Step-by-step explanation:
Answer:
v = 189 ft³
Step-by-step explanation:
v = lwh
v = 3 * 7 * 9
v = 189 ft³
Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Answer: y>(1/3)x-3
Step-by-step explanation: The slope is 1/3. The dotted line means it is not inclusive, and the value of k means it is going down three units.
Answer:
3
Step-by-step explanation:
Usually, when there is contamination the smallest amount can have huge ramifications in the data collected. In this scenario, if in a "clean" environment the trait is found in 2/10 frogs then anything above this number should be considered contaminated. This is because data above this ratio would be considered uncommon or rare and this unique occurrence can be most likely tied to the only new factor which would be the contamination. Therefore the minimum number of frogs with this trait in the sample would be 3.