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Hoochie [10]
3 years ago
7

Write a data set of any 5 numbers that has a median equal to 7

Mathematics
1 answer:
ELEN [110]3 years ago
5 0
Since there are 5 numbers, the median will be the middle number.

examples of answers to this question:   6 7 7 7 7 (median is 7)

1 2 7 7 9  (median is 7)

2 3 7 8 9 (median is 7)
You might be interested in
Solve plz plz try i have this being graded
Y_Kistochka [10]
It's w=2z+3



¯\_(ツ)_/¯
5 0
4 years ago
A horse is 17 hands tall at the hand equals 4 inches how tall is the horse in inches
Lilit [14]
<h3><u>68 inches</u></h3>

Because we know how large each hand is, we can multiply the number of hands by the amount of inches each one represents to find the total number of inches.

17 * 4 = 68


8 0
3 years ago
Read 2 more answers
Using power series, solve the LDE: (2x^2 + 1) y" + 2xy' - 4x² y = 0 --- - -- -
sattari [20]

We're looking for a solution of the form

y=\displaystyle\sum_{n\ge0}a_nx^n

with derivatives

y'=\displaystyle\sum_{n\ge0}(n+1)a_{n+1}x^n

y''=\displaystyle\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n

Substituting these into the ODE gives

\displaystyle\sum_{n\ge0}\left(\bigg(2(n+2)(n+1)a_{n+2}-4a_n\bigg)x^{n+2}+2(n+1)a_{n+1}x^{n+1}+(n+2)(n+1)a_{n+2}x^n\right)=0

Shifting indices to get each term in the summand to start at the same power of x and pulling the first few terms of the resulting shifted series as needed gives

2a_2+(2a_1+6a_3)x+\displaystyle\sum_{n\ge2}\bigg((n+2)(n+1)a_{n+2}+2n^2a_n-4a_{n-2}\bigg)x^n=0

Then the coefficients in the series solution are given according to the recurrence

\begin{cases}a_0=y(0)\\\\a_1=y'(0)\\\\a_2=0\\\\2a_1+6a_3=0\implies a_3=-\dfrac{a_1}3\\\\a_n=\dfrac{-2(n-2)^2a_{n-2}+4a_{n-4}}{n(n-1)}&\text{for }n\ge4\end{cases}

Given the complexity of this recursive definition, it's unlikely that you'll be able to find an exact solution to this recurrence. (You're welcome to try. I've learned this the hard way on scratch paper.) So instead of trying to do that, you can compute the first few coefficients to find an approximate solution. I got, assuming initial values of y(0)=y'(0)=1, a degree-8 approximation of

y(x)\approx1+x-\dfrac{x^3}3+\dfrac{x^4}3+\dfrac{x^5}2-\dfrac{16x^6}{45}-\dfrac{79x^7}{125}+\dfrac{101x^8}{210}

Attached are plots of the exact (blue) and series (orange) solutions with increasing degree (3, 4, 5, and 65) and the aforementioned initial values to demonstrate that the series solution converges to the exact one (over whichever interval the series converges, that is).

5 0
3 years ago
8. Caitlyn wants to build a fence around her flower garden,
ioda

Answer:

B

Step-by-step explanation:

5 0
3 years ago
I WiLL GiVe BrAnYeSt
Phoenix [80]

Answer:

the answer is 529

Step-by-step explanation:

divide 7,406 and 14 and the answer is 529

7 0
3 years ago
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