So a disc is a circle and the formula for the area of a circle is
so 3.14*6^2
=3.14*36
=<span>113.04
area=113cm^2</span>
Answer: The segment EF of the isoceles triangle ΔEFP is 10 units
Solution
If point P is equidistant from the vertices of ΔDEF, the segment PE must measure the same that the segment PF, then these two segments are congruent:
PE=PF
Then ΔEFP is an isisceles triangle, because it has two congruent sides (PE=PF), and the height of the side EF (PJ perpendicular to EF) divides ΔEFP into two congruent right triangles (ΔEJP and ΔFJP). The legs EJ and FJ must be congruent:
FJ=EJ
3x-1=x+3
Solving for x: Subtracting x and adding 1 both sides of the equation:
3x-1-x+1=x+3-x+1
2x=4
Dividing both sides of the equation by 2:
2x/2=4/2
x=2
Then:
FJ=3x-1→FJ=3(2)-1→FJ=6-1→FJ=5
EJ=x+3→EJ=2+3→EJ=5
EF=EJ+FJ→EF=5+5→EF=10
Answer:
308
Step-by-step explanation:
7x3x11=308
The word each means to multiply in math.
Answer:
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
For any value of x g(x) is always greater than h(x) and for any value of x, h(x) will always be greater than g(x) are not true.
The given function is:
g(x) = x^2 and h(x) = –x^2
x=0
g(0)=(0)^2 = 0
h(0)= -(0)^2 = 0
Now check the condition for x = -1
put x =-1 in the given functions.
g(x)=x^2
g(-1) = (-1)^2 = 1
h(x)= -x^2
h(-1) = -(-1)^2 = -1
g(x)>h(x)
Now take a positive value of x= 3
Put the value in the given functions:
g(3) = (3)^2 = 9
h(3) = -(3)^2 = -9
g(x)>h(x)
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x)....