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Answer:When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.
The chemical symbol for sodium carbonate is .
The decomposition of sodium carbonate is:
The decomposition of sodium bicarbonate, will result in the formation of sodium oxide, and carbon dioxide, .
Hence, carbon dioxide, will produce with sodium oxide, on decomposition of .
Explanation:Na2CO3 Na2O +CO2 CO2 is the answer
Answer:
0.036 M of
Explanation:
It is an example of acid-base neutralization reaction.
KOH + ----> +
Base Acid Salt
When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .
Molarity=
No.of moles= Molarity × Volume of the Particular Solution
Therefore,
------------------------------(1)
where
= Molarity of Acid
= Volume of Acid
= Molarity of Base
= Volume of Base
=0.3330 M
=10.62 mL
=98.2 mL
=??(in M)
Plugging in Equation 1,
0.3330 × 10.62 = × 98.2
=
=0.036 M
Reduction takes place in cathode while oxidation takes place at the anode.
Given that the reaction 3MnO4- +24H + +5Fe→3Mn+2+5Fe+3+12H2O
Now that oxidation is termed as an increase in oxidation number or loss of electrons while reduction is a decrease in oxidation number and gain of electrons,
∴oxidation will be
Fe→Fe +3+3e-
reduction will
MnO4- +8H+ →Mn+2+4H2O
If oxidation takes place at anode then Anode: an oxidation reaction
Fe→Fe+3+3e- . Then the answer is
Fe(s)→Fe+3(aq)+3e-