P * V = n R T
<span>1 * 2.50 = n * 0.082 * 273 = 2. 50 / ( 0.082 * 273 ) = 0.11 mol </span>
<span>mass = mole number * molecular mass </span>
<span>mass = 0.11 * ( 16 * 2 ) = 3.52 g </span>
Answer:
5 litres of solution are requried
Explanation:
Given that the typical units of
concentration
are
m
o
l
⋅
L
−
1
, to get
concentration
or
amount of moles
or
volume of solution
we just have to take the appropriate product or quotient.
We want
1.0
⋅
m
o
l
N
a
O
H
:
this the product
Volume of solution
×
Concentration
.
So we need the quotient:
Moles of solute
Concentration
=
1.0
⋅
m
o
l
0.2
⋅
m
o
l
⋅
L
−
1
=
5
⋅
L
.
(i.e.
1
1
⋅
L
−
1
=
1
⋅
L
)
Note that we go to such trouble in including the units in these calculations as an extra check on our arithmetic. Sometimes you ask yourself should I divide or should I multiply. Dimensional analysis answers our question. We wanted an answer in
litres
, and we got one. This persuades us that we did the calculation right.
Answer:
P = 0.0373 atm
Explanation:
Given data:
Mass of krypton = 1.86 g
Volume of krypton = 17.5 L
Temperature of krypton = 190 F
Pressure of krypton = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 1.86 g/ 83.9 g/mol
Number of moles = 0.022 mol
Formula:
PV = nRT
P = nRT / V
P = 0.022 mol × 0.0821 atm. L. mol⁻¹. K⁻¹ × 360.928 K / 17.5 L
P = 0.652 atm. L /17.5 L
P = 0.0373 atm
Answer:
Explanation:
Together with her husband, she was awarded half of the Nobel Prize for Physics in 1903, for their study into the spontaneous radiation discovered by Becquerel, who was awarded the other half of the Prize. In 1911 she received a second Nobel Prize, this time in Chemistry, in recognition of her work in radioactivity.
