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3 years ago

How many moles of H2O can be produced with 5.8 moles of O2 ?

Chemistry

1 answer:

Evgesh-ka [11]3 years ago

8 0

Answer:

1.78

Explanation:

1mole produce 18g/x will produce 32g then the answer is 1.78moles

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ANSWER FAST PLZZZ!!!!!!!!!!!!!

goldfiish [28.3K]

Answer:

1 and 2

Explanation:

1 is negative

2 is negative

3 is positive

5 0

3 years ago

How would you prepare 3.5 L of a 0.9M solution of KCl?

PolarNik [594]

$V=3,5L\\
Cm=0,9M\\
M_{KCl}=74\frac{g}{mol}\\\\
C_{m}=\frac{n}{V}\\\\
n=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV} \ \ \ \Rightarrow \ \ \ m=C_{m}MV\\\\
m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g$

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.

4 0

3 years ago

A gaseous mixture consisting of nitrogen, argon, and oxygen is in a 3.5-L vessel at 25C. Determine the number of moles of oxygen

Step2247 [10]

Answer:

Number of moles of oxygen = 0.037 mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂) = 98.5 KPa - 72.0 KPa

P(O₂) = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037 mol

6 0

3 years ago

A lead sphere has a mass of 1.20 x 104 g, and its volume is 1.05 x 103 cm^3. Calculate the density of lead.

Hatshy [7]

Answer: The density of lead will be $11.42g/cm^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of lead= $1.20\times 10^4g$

Volume of lead = $1.05\times 10^3cm^3$

Putting in the values we get:

$Density=\frac{1.20\times 10^4}{1.05\times 10^3}=11.42g/cm^3$

Thus density of lead will be $11.42g/cm^3$

4 0

3 years ago

When the n quantum number equals 1, we are in what orbital?

g100num [7]

Answer:

p orbital

Explanation:

8 0

3 years ago