How many moles of H2O can be produced with 5.8 moles of O2 ?
1 answer:
You might be interested in
The Calvin cycle, also called the light-independent or carbon fixation reactions, is the second stage of photosynthesis where water, and carbon dioxide (CO2) from air, are converted into organic compounds (i.e. sugars) using the energy from short-lived electronically excited carriers (ATP and NADPH) for the reactions. These organic compounds can then be used by the producing organism (i.e. plants) and the animals that feed on it.
One product of the Calvin cycle is the glyceraldehyde-3-phosphate (G3P), which is later on used in the production of glucose and in the regeneration of <span>Ribulose 1,5-bisphosphate (RuBP), which is an organic compound</span> essential to the reactions in the cycle.
One turn of Calvin Cycle produces 2 G3P molecules, each comprising of 3 carbons. This gives a total of 6 carbons. Five (5) of these carbons will be used to regenerate RuBP and only 1 will be available to form a surplus G3P later on. This surplus G3P will be used for the production of glucose (a 6-carbon sugar).
Thus, 3 turns of the carbon cycle will produce 1 surplus G3P. There are 8 sets of 3-turns in 24 cycles, therefore,
1 net G3P molecule * 8 sets of 3-turns = 8 G3P molecules
Therefore, there are 8 net or surplus G3P molecules produced for 24 cycles of the Calvin Cycle. The total G3P molecules produced, including the ones that participated in the regeneration of RuBP would be 48 G3Ps.
For every 3 turns, 6 G3P molecules are produced, 5 of which will be used in the regeneration of RuBP and 1 will be the net or surplus, to be used for the production of glucose. The 48 G3Ps then come from the calculation,
6 total G3P molecules * 8 sets of 3-turns = 48 G3P molecules
The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png).
One product of the Calvin cycle is the glyceraldehyde-3-phosphate (G3P), which is later on used in the production of glucose and in the regeneration of <span>Ribulose 1,5-bisphosphate (RuBP), which is an organic compound</span> essential to the reactions in the cycle.
One turn of Calvin Cycle produces 2 G3P molecules, each comprising of 3 carbons. This gives a total of 6 carbons. Five (5) of these carbons will be used to regenerate RuBP and only 1 will be available to form a surplus G3P later on. This surplus G3P will be used for the production of glucose (a 6-carbon sugar).
Thus, 3 turns of the carbon cycle will produce 1 surplus G3P. There are 8 sets of 3-turns in 24 cycles, therefore,
1 net G3P molecule * 8 sets of 3-turns = 8 G3P molecules
Therefore, there are 8 net or surplus G3P molecules produced for 24 cycles of the Calvin Cycle. The total G3P molecules produced, including the ones that participated in the regeneration of RuBP would be 48 G3Ps.
For every 3 turns, 6 G3P molecules are produced, 5 of which will be used in the regeneration of RuBP and 1 will be the net or surplus, to be used for the production of glucose. The 48 G3Ps then come from the calculation,
6 total G3P molecules * 8 sets of 3-turns = 48 G3P molecules
The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png).
This is an incomplete question, here is a complete question.
Consider the reaction:
Kc = 0.30 at some temperature.
If the initial mixture has the concentrations below, the system is_______.
Chemicals Concentration (mol/L)
- NO₂ 0.024
- CO 0.360
- NO 0.180
- CO₂ 0.120
Possible answers:
1) not at equilibrium and will remain in an unequilibrated state.
2) not at equilibrium and will shift to the left to achieve an equilibrium state.
3) not at equilibrium and will shift to the right to achieve an equilibrium state.
4) at equilibrium
Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.
Explanation:
Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
First we have to determine the value of reaction quotient (Qc).
The given balanced chemical reaction is,
The expression for reaction quotient will be :
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Now put all the given values in this expression, we get
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
There are 3 conditions:
When that means product > reactant. So, the reaction is reactant favored.
When that means reactant > product. So, the reaction is product favored.
When that means product = reactant. So, the reaction is in equilibrium.
The given equilibrium constant value is,
From the above we conclude that, the that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.
Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.