It doesn't obey the octet rule.
Both have a continuous light spectra the fluorescent source makes a spectra with more intense bands of mercury
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Answer:
pH = 6.20
Explanation:
<em>The pKa of cacodylic acid is 6.</em>
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To solve this question we must use Henderson-Hasselbalch equation:
pH = pKa +log [A⁻] / [HA]
<em>Where pKa is the pKa of the weak acid = 6</em>
<em>And [] could be taken as the moles of A⁻ the conjugate base, and HA, the weak acid.</em>
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The moles of the NaOH added to the solution of the weak acid are = Moles A⁻
And moles HA = Initial moles HA - Moles NaOH added
Initial moles HA:
0.0200L * (0.130mol / L) = 0.00260 moles
Moles NaOH:
0.0200L * (0.0800mol / L) = 0.00160 moles = [A⁻]
Moles HA =
0.00260 moles - 0.00160 moles = 0.00100 moles = [HA]
pH = 6 +log [0.00160 moles] / [0.00100 moles]
<h3>pH = 6.20</h3>
Answer:
Energy is transferred between products and reactants.
Explanation:
took the k12 quiz and got it correct