What is the ratio of hydrogen(H) to oxygen(O) in hydrogen peroxide(H2O2)?

What is the mole fraction of potassium dichromate, K2Cr2O7, in a solution prepared from 24.42 g of potassium dichromate and 240.

Harrizon [31]

Answer:

$6.19\times 10^{-3}$ is the mole fraction of potassium dichromate.

Explanation:

Mass of potassium dichromate = 24.42 g

Moles of potassium dichromate = $n_1=\frac{24.42 g}{294.185 g/mol}=0.0830 mol$

Mass of water = 240.0 g

Moles of water = $n_2=\frac{240.0 g}{18.015 g/mol}=13.3222 mol$

Mole fraction is calculated by:

$\chi_1=\frac{n_1}{n_1+n_2}$

$\chi_1=\frac{0.0830 mol}{0.0830 mol+13.3222 mol}=0.00619=6.19\times 10^{-3}$

$6.19\times 10^{-3}$ is the mole fraction of potassium dichromate.

8 0

3 years ago

¿ que característica tiene el conocimiento científico ?

saw5 [17]

Answer: El conocimiento científico es un saber crítico (fundamentado), metódico, verificable, sistemático, unificado, ordenado, universal, objetivo, comunicable (por medio del lenguaje científico), racional, provisorio y que explica y predice hechos por medio de leyes.

Explanation: El conocimiento científico es un saber crítico (fundamentado), metódico, verificable, sistemático, unificado, ordenado, universal, objetivo, comunicable (por medio del lenguaje científico), racional, provisorio y que explica y predice hechos por medio de leyes.

7 0

3 years ago

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly

trapecia [35]

Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.

Solution : Given,

Mass of $Ag_2O$ = 25.0 g

Mass of $C_{10}H_{10}N_4SO_2$ = 50.0 g

Molar mass of $Ag_2O$ = 231.7 g/mole

Molar mass of $C_{10}H_{10}N_4SO_2$ = 250.3 g/mole

Molar mass of $AgC_{10}H_{9}N_4SO_2$ = 357.1 g/mole

First we have to calculate the moles of $Ag_2O$ and $C_{10}H_{10}N_4SO_2$ .

$\text{ Moles of }Ag_2O=\frac{\text{ Mass of }Ag_2O}{\text{ Molar mass of }Ag_2O}=\frac{25.0g}{231.7g/mole}=0.1079moles$

$\text{ Moles of }C_{10}H_{10}N_4SO_2=\frac{\text{ Mass of }C_{10}H_{10}N_4SO_2}{\text{ Molar mass of }C_{10}H_{10}N_4SO_2}=\frac{50.0g}{250.3g/mole}=0.1998moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Ag_2O(s)+2C_{10}H_{10}N_4SO_2(s)\rightarrow 2AgC_{10}H_9N_4SO_2(s)+H_2O(l)$

From the balanced reaction we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 1 mole of $Ag_2O$

So, 0.1998 moles of $C_{10}H_{10}N_4SO_2$ react with $\frac{0.1998}{2}=0.0999$ moles of $Ag_2O$

From this we conclude that, $Ag_2O$ is an excess reagent because the given moles are greater than the required moles and $C_{10}H_{10}N_4SO_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgC_{10}H_9N_4SO_2$

From the reaction, we conclude that

As, 2 mole of $C_{10}H_{10}N_4SO_2$ react with 2 mole of $AgC_{10}H_9N_4SO_2$

So, 0.1998 mole of $C_{10}H_{10}N_4SO_2$ react with 0.1998 mole of $AgC_{10}H_9N_4SO_2$

Now we have to calculate the mass of $AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=\text{ Moles of }AgC_{10}H_9N_4SO_2\times \text{ Molar mass of }AgC_{10}H_9N_4SO_2$

$\text{ Mass of }AgC_{10}H_9N_4SO_2=(0.1998moles)\times (357.1g/mole)=71.35g$

Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.

8 0

3 years ago

Where can we find petroleum? and how is it formed?

Alenkasestr [34]

It is found in underground reservoirs where pressure is extremely high and it is formed by the remains of ancient marine organisms. It is a fossil fuel

5 0

3 years ago

At most, how many bright fringes can be formed on one side of the central bright fringe (not counting the central bright fringe)

lilavasa [31]

Where are the answer choies ?

4 0

4 years ago