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AURORKA [14]
3 years ago
12

Element in the noble ga family are considered stabled because their outer energy levels are

Chemistry
1 answer:
blsea [12.9K]3 years ago
3 0

Answer: In octet state.

Explanation: For noble gases they are stable in state since their outer shell contain fully occupied having 8 electrons.

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What is the name of the compound Sr3N2?
nadezda [96]
The answer is Strontium Nitride
5 0
3 years ago
An ionic bond can be formed when one or more electrons are
xz_007 [3.2K]

Answer:

Are transferred completely from the valence shell of an element to the other

Explanation:

Basically, to form a chemical bond, you either transfer or you share. When you share, it is a case of covalent bonding which can be in several other forms. When there is a transfer, it is a case of ionic bonding.

The basic explanation for this is that while some atoms are electronically sufficient, some are electronically deficient. This means while some atoms are having an excess number of electrons, then some are having less number of electrons.

To satisfy both parties, there must be a transfer if electrons between the two parties. While the one with the excess numbers serves as the donor, the one with insufficient number of electrons serve as the acceptor

8 0
3 years ago
Substances that dissolve in water nd give up OH-ions are considered what
just olya [345]

Your answer would be an Arrhenius base

Hope this helps

7 0
2 years ago
Find the mass of 1.112 moles HF?
Alexeev081 [22]

Answer:

22.25 g

Explanation:

To find the mass, you need to convert moles to grams and get 22.25 g.

7 0
3 years ago
A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

Q_1=-Q_2

Mass of steel= m_1

Specific heat capacity of steel = c_1=0.452 J/g^oC

Initial temperature of the steel = T_1=2.00^oC

Final temperature of the steel = T_2=T=21.50^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2= 105 g

Specific heat capacity of water=c_2=4.18 J/g^oC

Initial temperature of the water = T_3=22.00^oC

Final temperature of water = T_2=T=21.50^oC

Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))

On substituting all values:

(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}

<h3>25.0 grams is the mass of the steel bar.</h3>
3 0
3 years ago
Read 2 more answers
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