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Tom [10]
3 years ago
12

16. A map is drawn on a coordinate plane.

Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:

can't answer without the picture because you need the route to know how far.

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On a coordinate plane, triangle J K L has points (negative 2, 1), (0, 3), and (2, negative 1). Reflect the figure over the line
svetlana [45]

Answer:

J'(2, 1)

K'(0, 3)

Step-by-step explanation:

On a coordinate plane, coordinates of the points J, K and L are (-2, 1), (0, 3) and (2, -1) respectively.

If we reflect these points over the line x = 0 or y-axis, rule to be followed is

(x, y) → (-x, y)

Only sign of x coordinates get changed while y coordinates remain the same.

Following this rule coordinates of the images of J' and K' will be

J(-2, 1) → J'(2, 1)

and K(0, 3) → K'(0, 3)

6 0
3 years ago
Read 2 more answers
What is the solution to 2x+1=-7x+19
joja [24]
The answer is x equals 2
7 0
3 years ago
Francisco needed to get his computer fixed. He took it to the repair
grin007 [14]

Answer:

  $95 per hour

Step-by-step explanation:

The total of charges is the sum of the cost of labor and the cost of parts. The cost of labor is the product of hours (5) and the cost per hour (x). Then the equation for total cost is ...

  total cost = parts cost + hours cost

  651 = 176 + 5x

  475 = 5x . . . . . . . subtract 176

  95 = x . . . . . . . . . divide by 5

The cost of labor per hour is $95.

6 0
3 years ago
Enter the value of P so that the expression 4(10+n) is equivalent to 4(n+p)
Paraphin [41]

Answer:

I think it is 10

Step-by-step explanation:

Only because I believe n is still unknown and 4 must be multiplied

example

4(10 + n)

40 + 4n

now if P = 10

4(n + p)

4(n + 10)

4n + 40

8 0
3 years ago
Read 2 more answers
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
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