°C = (5/9) · (°F-32)
The "wet" thermometer is the upper one ... you can see the wet cloth wrapped around the bulb at the end. It's reading 70° F.
°C = (5/9) · (38) = 21.1° C
The "dry" thermometer is the lower one. It's reading 80° F.
°C = (5/9) · (48) = 26.7° C
So it looks like choice-A is your answer.
Answer:
1 . What happens when you drop the stone?
Depending on the weight from which the stone was dropped, the glass might well break
2 depending on the size and weight and shape on the stone the glass might well break
3 depending on the density on the stone the stone might when float on the water
Explanition :
GIVE ME BRAINLESS PLEASE !!
Answer:
Explanation:
We shall represent displacement in vector form .Consider east as x axes and north as Y axes west as - ve x axes and south as - ve Y axes . 255 km can be represented by the following vector
D₁ = - 255 cos 49 i + 255 sin49 j
= - 167.29 i + 192.45 j
Let D₂ be the further displacement which lands him 125 km east . So the resultant displacement is
D = 125 i
So
D₁ + D₂ = D
- 167.29 i + 192.45 j + D₂ = 125 i
D₂ = 125 i + 167.29 i - 192.45 j
= 292.29 i - 192.45 j
Angle of D₂ with x axes θ
tan θ = -192.45 / 292.29
= - 0.658
θ = 33.33 south of east
Magnitude of D₂
D₂² = ( 192.45)² + ( 292.29)²
D₂ = 350 km approx
Tan
C) total linear momentum of the ball and cannon is conserved.
Basically it happens that in the beginning before there is a momentum acting on the two bodies, these are a unique system. Here the total momentum of the System is 0. However, when the positive momentum of the cannonball is added, the system will be immediately affected by a negative momentum which will pull back the cannon. Could this be extrapolated as a condition of Newton's third law.
Answer:
It's B
Explanation:
Hope this helps, tell me if im wrong!
