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Nezavi [6.7K]
3 years ago
13

Identify the mathematical relationship that exists between pressure and volume, when temperature and quantity are held constant,

as being directly proportional or inversely proportional. Explain your answer and write an equation that relates pressure and volume to a constant, using variables, not the mathematical equation from the best fit line.
Physics
1 answer:
RSB [31]3 years ago
7 0

Answer:

BOYLE'S Law

Explanation:

Boyle's law states that at constant temperature the volume of a fixed quantity of an ideal gas is inversely proportional to the pressure of the gas.

Mathematically:

From the universal gas law we have:

P.V=n.R.T

where:

P = pressure of the gas

V = volume of the gas

n = no. of moles of gas

T = temperature of the gas

R = universal gas constant

when the mass of gas is fixed i.e. n is constant and temperature is also constant.

PV=constant

P\propto\frac{1}{V}

P_1.V_1=P_2.V_2

here the suffix 1 and 2 denote two different conditions of the same gas.

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A skateboarder shoots off a ramp with a velocity of 7.1 m/s, directed at an angle of 61° above the horizontal. The end of the ra
dsp73

Answer:

Highest point reached  = 3.37 m

Explanation:

Initial velocity, = 7.1 m/s

Initial vertical velocity = 7.1 sin 61 = 6.21 m/s

Consider the vertical motion of skateboarder,

We have equation of motion, v² = u² + 2as

          Initial velocity, u = 6.21 m/s

          Acceleration, a = -9.81 m/s²

          Final velocity, v = 0 m/s

         Substituting

                       v² = u² + 2as

                       0² = 6.21² + 2 x -9.81 x s

                       s = 1.97 m

So from ramp the position it goes up by 1.97 m

       Highest point reached = 1.97 + 1.4 = 3.37 m    

6 0
3 years ago
A contestants spin a wheel when it is their turn in a game show. One contestant gives the wheel an initial angular speed of 3.40
guajiro [1.7K]

Answer:

4.62 s

Explanation:

We are given that

Initial angular speed,\omega=3.4 rad/s

\theta=1\frac{1}{4} rev=\frac{5}{4}\times 2\pi=2.5\pi rad

\omega'=0

\omega'^2-\omega^2=2\alpha \theta

Substitute the values

0-(3.4)^2=2\times 2.5\pi \alpha

\alpha=\frac{-(3.4)^2}{2\times 2.5\pi}=-0.736 rad/s^2

\omega'=\omega+\alpha t

0=3.4-0.736 t

-0.736t=-3.4

t=\frac{-3.4}{-0.736}=4.62 s

Hence, the wheel takes 4.62 s to come to rest.

3 0
3 years ago
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