First of all we state the formula
Power=work done/time
we can rearrange this formula as well
work done=power x time
Since the SI unit of time is in seconds we change the minutes to seconds
2mins= 60x2 = 120 seconds
Using our formula (work done=power x time) we simply put in the values
work done = 4500 x 120
work done = 540,000J
From p1v1/t1 = p2v2/t2
pressure unchanged ... cancelled out
v1=605 , t1=27C = 300K,
t2=-3C = 270K
***remember temperature must be in Kelvin
we got
605/300 = v2/270
v2 = 545
Answer:
d. 332 V
Explanation:
Given;
number of turns in the wire, N = 40 turns
area of the coil, A = 0.06 m²
magnitude of the magnetic field, B = 0.4 T
frequency of the wave, f = 55 Hz
The maximum emf induced in the coil is given by;
E = NBAω
Where;
ω is angular velocity = 2πf
E = NBA(2πf)
E = 40 x 0.4 x 0.06 x (2 x π x 55)
E = 332 V
Therefore, the maximum induced emf in the coil is 332 V.
The correct option is "D"
d. 332 V
Answer:
A) reduced air pressure on the ball.
Explanation:
Answer:heed
Explanation:
heed knows how to divide.