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hichkok12 [17]
3 years ago
13

the number of dogs compared to the number of cats owners by the residents of an apartment complex is represented by the model ho

w many cats are there of eight dogs and apartment complex is there eight dogs and there are blank cats
Mathematics
1 answer:
Burka [1]3 years ago
7 0

Answer:

Its two and Four,

Step-by-step explanation:

The ratio is two dogs to 4 cats.

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
2. Eric had $197 in his savings account before he was paid his weekly salary. His current
umka21 [38]

Answer:

kkkkkkkiooooooooooooooooooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

kkkkkkkkkkkiiiiiiiiiiiiiiiiiiiiiiiioooooooooooooooooo

6 0
3 years ago
What is the answer to this 3-(|-4|-|-5|)
Sholpan [36]
60 because all the negatives would cancel out so all you have to do is multiply the numbers
7 0
3 years ago
Which of the following paints is a solution
Anton [14]
I believe the first one is c
7 0
4 years ago
Luke is making pancakes. The recipe calls for 0.5 quart of milk and 2.5 cups of flour. He has 3/8 quart of milk and 18/8 cups of
cupoosta [38]
<span>3/8 ÷ 0.5 = 3/4 
2.5 ÷ 18/8 = 2/5 

Since 3/4 > 2/5, he has too much milk. He'll get runny pancakes.Hope this helps! =)</span>
3 0
4 years ago
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