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3 years ago

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The table shows sets of ordered pairs that form a relation. Does each set of ordered pairs represent a function? Select Function

or Not a Function for each set of ordered pairs. Set of ordered pairs Function Not a Function {(1,7),(−1,7),(8,−6),(−3,2)} {(4,7),(−1,2),(4,−6),(−3,−2)} {(3,7),(−1,2),(−4,−2),(−3,−2)} {(−3,7),(1,2),(4,−2),(12,−4)}

1 answer:

Ierofanga [76]3 years ago

6 0

The set of ordered pairs {(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)} is a function

The set of ordered pairs {(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)} is not a

function

The set of ordered pairs {(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)} is a function

The set of ordered pairs {(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)} is a function

Step-by-step explanation:

An ordered pair represents a relationship between two values

The first value is the input the second value is the output

1. A relation is a set of inputs and outputs

2. A function is a relation with one output for each input

3. All functions are relations

{(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(1 , 7) , (−1 , 7) , (8 , −6) , (−3 , 2)} is a function

{(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)}

∵ The x-coordinate 4 has two values of y (7 and -6)

∴ The relation above is not a function

The set of ordered pairs {(4 , 7) , (−1 , 2) , (4 , −6) , (−3 , −2)} is not a

function

{(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(3 , 7) , (−1 , 2) , (−4 , −2) , (−3 , −2)} is a function

{(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)}

∵ Each x-coordinate in each ordered pair has only one y-coordinate

∴ The relation above is a function

The set of ordered pairs {(−3 , 7) , (1 , 2) , (4 ,−2) , (12,−4)} is a function

Learn more:

You can learn more about function in brainly.com/question/10382470

#LearnwithBrainly

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we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $\frac{y}{x}=k$ or $y=kx$

where

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$\frac{8}{5}=k$

therefore

<u>the answer is</u>

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While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

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Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

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The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

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Answer:

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Given: a graph

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A rate of change of one quantity with respect to another quantity is known as rate of change. If y is the dependent variable and x is the independent variable then average rate of change = change in y /change in x.

From the graph,

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