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Dafna11 [192]
3 years ago
5

Todd begins piano practice at 4:15 pm and ends at 5:50 pm. How long does he practice.

Mathematics
2 answers:
AveGali [126]3 years ago
5 0
Todd practiced for 1:45 minutes because of you subtracted 5:50 minus 4:15 it would equal 1:45 hope that helped
julia-pushkina [17]3 years ago
3 0
Distance between 4:15 and 5:50 is 95 minute

So he practiced for 95 min 
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Help plz<br>6(2x - 11) + 15 = 3x + 12​
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Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

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6 × -11 = -66

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Calculate the x constant:

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Then the ones with no x:

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51 + 12 = 63

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Lastly, divide

63 ÷ 9 = 7

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-3x+7 x=-2<br> PLEASE SHOW WORK. Thanks
galben [10]

Answer:

1  :

Step  2  :

Equations which are never true :

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Solving a Single Variable Equation :

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3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

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If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

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0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

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3 years ago
Help please!! 5th grade math.
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