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SVETLANKA909090 [29]

3 years ago

13

PLS HELP ME ASAP LIKE NOW PLSSSSS WILL GIVE 30 POINTS AND BRAINLIEST BUT I NEED THE ANWSER NOW PLS!!!!!!! ( Respond the question

that are in the picture)

2 answers:

VLD [36.1K]3 years ago

8 0

Answer:

The answer to part A is 15 cm because you would first divide 16 by two to find the base of one triangle. Then you would do the pythagorean theorem to find the height. <em> I don't know if that would help.</em>

The answer to part B is 240 cm squared because you would find the area of one right triangle and multiply it by 4 to find the area of all the sides of the box.

Step-by-step explanation:

GrogVix [38]3 years ago

7 0

$20 \times 16 = 320 \\ 2 \times v \div 320 = h \\ h = 15$
answer to the first question

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Read the question below.

kipiarov [429]

Answer:

$ 6.8

Step-by-step explanation:

20% of 34 dollars is 6.8

8 0

2 years ago

Can i please get help on 46,66,66, and 74

Mrac [35]

The answer to 46 is = 10

Hope this helps some I don’t know the rest but have a good night

5 0

3 years ago

Show work plz, NEED HELP FAST PLZ

german

Answer:what are the answer choices

Step-by-step explanation:

3 0

2 years ago

6. Calculate the area of the octagon in the<br> figure below.

Kryger [21]

Answer:

$41\text{ [units squared]}$

Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

4 triangles (corners)
3 rectangles (one in the middle, two on top after you remove triangles)

<u>Formulas</u>:

Area of rectangle with length $l$ and width $w$ : $A=lw$
Area of triangle with base $b$ and height $h$ : $A=\frac{1}{2}bh$

<u>Area of triangles</u>:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is $A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}$

The area of all four is then $2\cdot 4=8$ units squared.

<u>Area of rectangles</u>:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of $3\cdot 2=6$ units squared, and the both of them have a total area of $6\cdot 2=12$ units squared.

The last rectangle has a width of 7 and a height of 3 for a total area of $7\cdot 3=21$ units squared.

Therefore, the area of the entire octagon is $8+12+21=\boxed{41\text{ [units squared]}}$

4 0

3 years ago

Find the x-intercepts of the parabola with vertex (5,-4) and y-intercept (0,96). Write your answer in this form: (x1,y1),(x2,y2)

lesya692 [45]

Answer:

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

Step-by-step explanation:

we know that

The equation of the given parabola is

$(y-k)=a(x-h)^{2}$

we have

the vertex is the point (5,-4)

substitute

$(y+4)=a(x-5)^{2}$

The y-intercept is the point (0,96)

substitute and solve for a

$(96+4)=a(0-5)^{2}$

$100=a(25)$

$a=100/25=4$

The equation of the vertical parabola is equal to

$(y+4)=4(x-5)^{2}$

Find the x-intercepts

Remember that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$4=4(x-5)^{2}$

Simplify

$1=(x-5)^{2}$

Rewrite

$(x-5)^{2}=1$

square root both sides

$(x-5)=(+/-)1$

$x=(+/-)1+5$

$x=(+)1+5=6$

$x=(-)1+5=4$

therefore

The x-intercepts are

(x1,y1)=(4,0)

(x2,y2)=(6,0)

4 0

3 years ago