2. W<5
4. D<6 (or equal to)
Answer:
Domain = {All real values of x EXCEPT x = -5 and x = 7}
Step-by-step explanation:
This is a rational function given as y=\frac{6+9x}{6-|x-1|}y=
6−∣x−1∣
6+9x
The domain is the set of all real value of x for which the function is defined.
For rational functions, we need to find which value of x makes the denominator equal to 0. We need to exclude those values from the domain.
Now
6 - |x-1| = 0
|x-1| = 6
x- 1 = 6
or
-(x-1) = 6
x = 6+1 = 7
and
-x+1=6
x = 1-6 = -5
So, the x values of -5 and 7 makes this function undefined. So the domain is the set of all real numbers except x = -5 and x = 7
We know:
We have
Substitute:
Only 4 and 10 meet the requirements of the question.
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40 and 1 NOT, because 40 > 12
20 and 2 NOT, because 20 > 12
5 and 8 NOT because GCF(5, 8) = 1
