Answer:2
Step-by-step explanation:
It's B
Slope is negative, the other must be positive due to m1 x m2 = - 1
m1 = -2/5
The diagram shows a gradient of -2/5. So, the
reciprocal of this valve to make - 1 is 5/2 (which is the - 2/5 flipped upside down, but positive)
-2/5 x 5/2 = - 10/10 (or - 1)
Thus, the perpendicular line to this has a gradient of 5/2.
Hope this helps!
Answer:
the question is incomplete, so I looked for similar ones
the number of bottles of water remaining as a function of time:
f(x) = -78x + 468
1.3 bottles are sold per minute x 60 minutes per hour = 78 bottles per hour
x = number of hours
the slope is -78
the y intercept is 468
domain = 0 ≤ x ≤ 7.5 hours (from 10 AM to 5:30 PM)
range = 0 ≤ y ≤ 468 bottles
the snack will run out of bottles of water by 4 PM
78x = 468
x = 468 / 78 = 6 hours
if the snack wants to have enough bottles of water to serve all its customers, it will need:
78 x 7.5 hours = 585 bottles of water
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
