Combine another pipe and another
1 answer:
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Answer:
Step-by-step explanation:
Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61
To list: numbers from least to greatest
Solution:
Let the three consecutive odd integers be .
According to question,
So, the integers are
Numbers from least to the greatest:
We are told that f(x) = x + 2. We want to find .
Squaring f(x) on one side means we square x + 2 on the other.
So,
f(x) = x + 2
(f(x))² = (x + 2)²
= (x + 2)(x + 2)
We can use FOIL to square x + 2. The first terms multiply to x², the outside terms to 2x, the inside terms to 2x and the last terms to 4.
= x² + 2x + 2x + 4
= x² + 4x + 4
So [f(x)]² = x² + 4x + 4