Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
We'd need more information like the relationship between those equations.
Step-by-step explanation:
There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula
(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4
(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A
Answer: The correct answer is B. 523.3...cm^3
Step-by-step explanation:
4/3*pi*r^3 is the formula
first, divide the diameter by 2 to get the radius, now, you will begin solving.
4/3*5^3*3.14
5*5*5=125
4/3*125*3.14
125*3.14=392.5
4/3*392.5
523.3...
