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2 years ago

Combine another pipe and another

Mathematics

1 answer:

telo118 [61]2 years ago

8 0

Answer:

3 and 3/8

Step-by-step explanation:

1, and 4/8 + 1, and 6/8 = 3 and 2/8

3 and 2/8 + 1/8 = 3 and 3/8

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Ayudaaa es urgente por favor :(

rjkz [21]

3 /24 porque es 1/12

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2 years ago

Rewrite the following expression using base only once 7^6 x 7^8

chubhunter [2.5K]

Answer:

$7^{14}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , then

$7^{6}$ × $7^{8}$ = $7^{(6+8)}$ = $7^{14}$

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2 years ago

PLEASE HELP ME ASAP!!!

Olenka [21]

Answer:

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Step-by-step explanation:

8 0

2 years ago

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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

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2 years ago

Round 584,565 to the nearest hundred thousand.

lora16 [44]

Answer:

600,000

Step-by-step explanation:

600,000

8 0

2 years ago

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