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3 years ago

5

Each marble bag sold by Debra's Marble Company contains 8 yellow marbles for every 4 blue marbles. If a bag has 56 yellow marble

s, how many blue marbles does it contain?

1 answer:

laiz [17]3 years ago

4 0

Answer:

28 blue marbles

Step-by-step explanation:

yellow: blue

8 4

To get to 56 yellow marbles multiply by 7

yellow: blue

8*7 4*7

56 28

There will be 28 blue marbles

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A street light is mounted at the top of a 15-ft-tall pole. A man 6 feet tall walks away from the pole with a speed of 5 ft/s alo

harina [27]

Answer:

25/3 ft/s

Step-by-step explanation:

Height of pole , h=15 ft

Height of man, h'=6 ft

Let BD=x

BE=y

DE=BE-BD=y-x

All right triangles are similar

When two triangles are similar then the ratio of their corresponding sides are equal.

Therefore,

$\frac{AB}{CD}=\frac{BE}{DE}$

$\frac{15}{6}=\frac{y}{y-x}$

$\frac{5}{2}=\frac{y}{y-x}$

$5y-5x=2y$

$5y-2y=5x$

$3y=5x$

$y=\frac{5}{3}x$

Differentiate w.r.t t

$\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}$

We have dx/dt=5ft/s

Using the value

$\frac{dy}{dt}=\frac{5}{3}(5)=\frac{25}{3}ft/s$

Hence, the tip of his shadow moving with a speed 25/3 ft/s when he is 45 feet from the pole.

8 0

3 years ago

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Petrolyn motor oil is a combination of natural oil and synthetic oil. it contains 5 liters of natural oil for every 6 liters of

stepan [7]

In this problem, we use the method of ratio and proportion. This technique works by using the concept that there is a fixed ratio of compositions within a mixture. Speaking generally, there is a fixed ratio of the parts of the whole. So, all we have to do is equate both ratios.

5 L natural oil/ 6 L synthetic oil = x L natural oil/498 L synthetic oil
x = 415 L natural oil

So, if petrol oil contains 498 L synthetic oil, it has a corresponding amount of 415 natural oil. Adding these two would be the total volume of the petrol oil. That would be 415+498 = 913 L petrol oil.

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4 years ago

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

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4 years ago

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vampirchik [111]

Answer:

Step-by-step explanation:

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Help find missing side set up cosine ratio to solve???

kramer

Answer:

Step-by-step explanation:

Yes!

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3 years ago

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