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2 years ago

HELP DUE IN 15 MINS!

Mathematics

2 answers:

bonufazy [111]2 years ago

7 0

<h3>False</h3>

trust me the answer is false :)

s2008m [1.1K]2 years ago

6 0

Answer:

No they are not, false

Step-by-step explanation:

We know that if the diagonals are perpendicular then they cut at 90 degrees but in rectangles, the diagonals dont cut at 90 degrees. Hence the statement is false.

Would be amazing if you marked this brainliest :)

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Find the missing angle 25 points plus a thanks, 5 star and brainliest

irina1246 [14]

tan ? = 22/48

tan ? = 11/24

tan ? = 0.4583

? = 24.62 degrees ( approximately )

4 0

2 years ago

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Find the value of x. Round to the nearest degree. 60 33 57 29

stepan [7]

Answer:

Step-by-step explanation:

that is pretty close to a 45 degree angle so i would say about 33

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3 years ago

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What is the value of x2y, when x = 10 and y = 1? 1/10 1/5 5 10

jasenka [17]

Answer:

20 is the answer

Step-by-step explanation:

10× 2× 1 = 20

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2 years ago

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I WILL GIVE BRAINLIEST PLEASE HELP 12^13–12^12+12^11 is by 7 and 19.

Natali5045456 [20]

Answer:

(12^11)(19×7)

Step-by-step explanation:

12^13–12^12+12^11

(12^11)(12² - 12 + 1)

(12^11)(144 - 12 +1)

(12^11)(133)

(12^11)(19×7)

Therefore,

12^13–12^12+12^11 is a multiple of 19 and 7.

12^13–12^12+12^11 is divisible by 19 and 7.

4 0

3 years ago

How long will it take for $2500 to double if it is invested at 6% annual interest compounded 6 times a year? Enter exact calcula

12345 [234]

Answer:

Part 1) $t=11.610\ years$

Part 2) $t=11.552\ years$

Step-by-step explanation:

Part 1) we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06\\n=6$

substitute in the formula above

$5,000=2,500(1+\frac{0.06}{6})^{6t}$

$2=(1.01)^{6t}$

Apply log both sides

$log(2)=log[(1.01)^{6t}]$

$log(2)=(6t)log(1.01)$

solve for t

$t=log(2)/[6log(1.01)]$

$t=11.610\ years$

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06$

substitute in the formula above

$5,000=2,500(e)^{0.06t}$

$2=(e)^{0.06t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.06t}]$

$ln(2)=(0.06t)ln(e)$

$ln(2)=(0.06t)$

$t=ln(2)/(0.06)$

$t=11.552\ years$

3 0

2 years ago