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emmainna [20.7K]
3 years ago
12

A bike is traveling at a speed of 15 m/s. The mass of the bike is 30 kg. What is the kinetic

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

<h2>3375 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 30 \times  {15}^{2} \\  = 15 \times  {15}^{2}  \\  =  {15}^{3}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>3375 J</h3>

Hope this helps you

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Joe is hiking through the woods when he decides to stop and take in the view. He is particularly interested in three objects: a
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Answer:

A) correct answer is C,   B)   correct answer is b  and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

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where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

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let's apply this expression to our case

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so that the image is formed on the retina THE SAME AS

correct answer is C

B) The squirrel is at a smaller distance (p ') than the tree (p), therefore if we substitute in the equation above we find that q must decrease. Consequently the image is in front of the retina

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6 0
3 years ago
A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang
olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: s_c = \omega_ct = 0.233t

For the horse: s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

s_c = s_h

0.233t = 1.57 + 0.0068t^2

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t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}

t= \frac{0.233\pm0.11}{0.0136}

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Two plates of area 30.0 cm^2 are separated by a distance of 0.0590 cm. If a charge separation of 0.0240 μC is placed on the two
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Answer:

V=533.33 V

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V=\dfrac{0.0240\times 10^{-6}} {4.5\times 10^{-11}}

V=533.33 V

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3 years ago
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