Yes, it possible to code the impact force using an accelerometer.
Accelerometers can be used to measure vibration on cars, machines, buildings, process control systems and safety installations
<h3>What is an Accelerometer ?</h3>
An accelerometer is a device that measures the vibration, or acceleration of motion of a structure.
- The force caused by vibration or a change in motion (acceleration) causes the mass to "squeeze" the piezoelectric material which produces an electrical charge that is proportional to the force exerted upon it.
- They can also be used to measure seismic activity, inclination, machine vibration, dynamic distance and speed with or without the influence of gravity.
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Answer:
<em>Since I can see no choices, I answered it in my own understanding.</em>
Brian - amplitude and frequency
Marcia - amplitude and longitudinal wave
Explanation:
"Sound" and "sound waves" are essential part of a person's life. They can be used for<u> communicating</u> and <u>detecting some object</u>s.
Brian loves singing in the shower which means that he is using a greater amplitude. Amplitude refers to the<em> intensity of the sound </em>or the amount of energy that a sound carries. When one sings in the shower, the sound cannot travel very far. It bounces immediately back to the person singing thus, making the sound bigger. Brian is also using a <em>different range of </em><em>frequency</em><em> compared to his normal way of talking.</em> The frequency of a normal male voice is normally 85 to 180 Hz. A person singing may have a frequency as high as 1,500 Hz.
Marcia talks loudly on the phone. This means that she is also using a greater amplitude because the intensity of her voice is big. Since she is using the telephone, this means that her voice travels in a longitudinal wave through the telephone. This allows her voice to reach to the person on the other end of the line.
Answer:
thinnest soap film is 206.76 nm
Explanation:
Given data
wavelength = 550 nm
index of refraction n = 1.33
to find out
What is the thinnest soap film
solution
we have wavelength λ = 550 nm
that is λ = 550 ×
m
and n = 1.3
we will find the thickness of soap film as given by formula that is
thickness = λ/2n
thickness = 550 ×
/ 2(1.33)
thickness = 206.76 ×
m
thinnest soap film is 206.76 nm
Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:

where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.
Gravitational force is given by, 
Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.
Gravitational force of the star on planet 1, 
Gravitational force of the star on planet 2, 
Ratio, 

Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.