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Roman55 [17]
3 years ago
7

a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C

)
Physics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

0.02976°C

Explanation:

Heat Supplied = mcø

ø = 500/(4*4200)

ø = 0.02976 °C

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4. The blades on a fan have a frequency of 15 Hz.
vichka [17]

Answer:

a) 4500 cycles b) 0.0667s c) 6.67s

Explanation:

a) 15 Hz= 15 cycles/ s

   5 mins= 300s

   15 cycles/s * 300s= 4500 cycles

b) Period= 1/ frequency

   Period= 1/ 15 cycles/s

   Period= 0.0667s

c) Period * number of revolutions= time

  0.0667 * 100= 6.67s

6 0
3 years ago
Which of the examples below is an example of convection?
nasty-shy [4]
Basking in the sun :)
3 0
3 years ago
What is the mass of a football player if they are running at 3.6 m/s with a momentum of 62.5kgm/s?
ioda

momentum = mass * velocity

62.5 = mass * 3.6

mass = 62.5/3.6

mass = 17.36 kg

7 0
3 years ago
15. A machine must move an object 15.1 meters by exerting a 121 Newton force. If the machine
Tcecarenko [31]

The power provided by the machine is 13.24 W.

Answer:

Explanation:

Power is determined as the ratio of work done by the system or on the system to the time interval. As the work done is equal to the product of force acting on the system or by the system with the  displacement experienced by the system. The power provided by the machine will be

Power = Work done /Time

As the force is given as 121 N and the displacement is given as 15.1 m in a time interval of 2.3 minutes. The time interval should be changed to seconds for each solving ability.

Time taken = 2.3 * 60 s = 138 s

Power = (121×15.1)/138 = 13.24 W.

So the power provided by the machine is 13.24 W.

6 0
3 years ago
During 9.97 seconds a motorcyclist changes his velocity from v1,x = -36.5 m/s and v1,y = 10.9 m/s to v2,x =-21.9 m/s and v2,y =
svetoff [14.1K]

Average acceleration is defined as

a = \frac{v_f - v_i}{t}

here

v_f = final\: speed

v_i = initial\: speed

t = time

now for x direction we can say

a_x = \frac{v_{2x} - v_{1x}}{t}

a_x = \frac{-21.9 + 36.5}{9.97}

a_x = 1.46 m/s^2

Similarly for Y direction

a_y = \frac{v_{2y} - v_{1y}}{t}

a_y = \frac{27.5 - 10.9}{9.97}

a_y = 1.66 m/s^2

so above is the acceleration in x and y directions

7 0
3 years ago
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