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3 years ago

Find the value of : 0.678 multiplied by 9.01/0.0234

Mathematics

1 answer:

Alla [95]3 years ago

5 0

Answer:

261.06 (Approx)

Step-by-step explanation:

Given:

Two number = 0.678,9.01/0.0234

Find:

Multiply

Computation:

⇒ 0.678,9.01/0.0234

⇒ 0.678 x [9.01/0.0234]

⇒ 6.10878 / 0.0234

⇒ 261.058874

261.06 (Approx)

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Nikolai has a jar filled with 120 marbles. he has 72 red marbles, 17 blue marbles, 13 green marbles, and 18 purple marbles. what

asambeis [7]

To find the probability of both of these occurring, you will multiply the probability of choosing a blue marble by the probability of choosing a purple marble (with no replacement after the first one).

Probability of choosing a blue marble: 17/120
Probability of choosing a purple marble: 18/119

17/120 x 18/119 = 3/140

You will have a 3/140 chance of both of these occurring.

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3 years ago

Find the distance between the points (3, 8) and (0,4).

Bingel [31]

Answer:

Step-by-step explanation:

(3,8) (0,4)

X1 = 3 X2 = 0

Y1 = 8 Y2 = 4

$D=\sqrt{(X1-X2)^{2}+ (Y1-Y2)^{2} }$

$D= \sqrt{(3-0)^{2} + (8-4)^{2} }$

Do what's in the parentheses so...

3-0= 3
8-4= 4

Now plug it in!

$D= \sqrt{(3)^{2}+(4)^{2} }$

Now you are going to finish the parentheses so...

(3)^2= 9
(4)^2= 16

Plug that in so that you have this...

$\sqrt{9+16}$

Add 9+16 to get...

$\sqrt{25}$

Then you are going to find the number or numbers that make this a perfect square...

$\sqrt{25}= 5$

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3 years ago

If the producer in a food chain has 1000 kcal of energy available, how much energy would each of the consumers have?

madam [21]

Answer:

Primary consumer = 100kcal

Secondary consumer = 10kcal

Tertiary consumer = 1kcal

Step-by-step explanation:

In a food chain, transfer of energy occurs when one organism feeds on another organism. However, only 10% of energy is transferred from one organism to another because energy is lost as heat when the organisms perform metabolism.

In a typical food chain consisting of a producer, a primary (1st), secondary (2nd) and tertiary (3rd) consumer, if there are 1000 kcal of energy available in the producer, then:

- Primary consumer will obtain; 10% of 1000Kcal

10/100 × 1000

Primary consumer = 100kcal of energy.

- Secondary consumer will obtain as follows; 10% of 100kcal available energy

= 10/100 × 100

Secondary consumer = 10Kcal of energy.

- Tertiary consumer will obtain as follows; 10% of 10Kcal of available energy.

= 10/100 × 10

Tertiary consumer = 1 kcal of energy.

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