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Rama09 [41]
3 years ago
6

What is the degree of the following Monomial -2f^2g^3h^5

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

10

Step-by-step explanation:

We have a monomial in 3 variables: f, g and h. Whenever a monomial has more than one variable, the degree is calculated as the sum of exponents of all the variables involved. The given monomial is:

-2f^{2}g^{3}h^{5}

The exponent of f is 2, exponent of g is 3 and exponent of h is 5.

The degree of this monomial would be the sum of all these three exponents.

So, the degree of given monomial is:

Degree = 2 + 3 + 5

Degree = 10

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Semmy [17]

Answer:

a. V = 10*8*x

b. V= 10*8*22.5

Step-by-step explanation:

b. V= 1800

3 0
2 years ago
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.
garik1379 [7]

Answer:

The 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =9.2 represent the sample mean 1

\bar X_2 =8.8 represent the sample mean 2

n1=27 represent the sample 1 size  

n2=30 represent the sample 2 size  

\sigma_1 =0.3 population standard deviation for sample 1

\sigma_2 =0.1 population standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =9.2-8.8=0.4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281  

0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519  

So on this case the 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

6 0
3 years ago
6x + 5y = 82<br> 2x + 5y = 54
vovikov84 [41]

Answer:

A) 6x + 5y = 82

B) 2x + 5y = 54  We'll multiply equation B) by -1

B) -2x -5y = -54 Then we'll add this to A)

A) 6x + 5y = 82

4x = 28

x = 7

y = 8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help me!! <br> solve 31 = x + 25.5
serious [3.7K]

Answer:

x = 5.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

31 = x + 25.5

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 25.5 on both sides:                    5.5 = x
  2. Rewrite:                                                      x = 5.5
6 0
3 years ago
Read 2 more answers
Help plz. i would greatly appreciate it​
vekshin1

Answer:

1) 5^2=25

2) 5^2=x

3) b^3=64

Step-by-step explanation:

To write logs of the form log_ba=x in their exponential form, you take the base b and put it to the power of x and then set that equal to a: b^x=a.

1. Here, b = 5, a = 25, and x = 2, so: 5^2=25

2. In this problem, b = 5, x = 2, and a = x, so: 5^2=x

3. Finally, here, b = b, a = 64, and x = 3, so: b^3=64

Hope this helps!

6 0
3 years ago
Read 2 more answers
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